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Wordle 858 5/6* old
⬛⬛⬛⬛⬛ 651 (max 5 indicated)
β¬›πŸŸ¨β¬›β¬›β¬› 46, max 6
β¬›β¬›πŸŸ¨πŸŸ¨πŸŸ© 2
πŸŸ¨β¬›πŸŸ©πŸŸ©πŸŸ© other one...
🟩🟩🟩🟩🟩

Wordle 858 3/6* new
πŸŸ©β¬›πŸŸ©β¬›β¬› 2 only
πŸŸ©πŸŸ©πŸŸ©β¬›β¬› other one
🟩🟩🟩🟩🟩
Today the new was lucky starter.
Small change code means that it no longer works with the worst possible case which guaranteed "this or better", since this meant I might miss using a word with a high chance of a much better result. So now I need to see how that works out in practice for a bit...
So now the maximum expected could increase after a turn, as happened with the old strategy today. The 5 indicated after line 1 is actually just likely rather than a fact with the current approach.

Thinking it through I need to be clearer in my aims. Either I want to avoid a high score or X at the cost of getting a bit worse average (what my code tried to do up to last night) or not (which is what my newest code actually is probably going to do)...
I might be trying to have cake and eat it here (nibble a bit without damaging the cake).
 
Last edited:
Wordle 859 3/6* old
πŸŸ©β¬›πŸŸ¨β¬›β¬› 10, max 5
πŸŸ©πŸŸ¨β¬›β¬›β¬› just 1
🟩🟩🟩🟩🟩

Wordle 859 5/6* new
β¬›πŸŸ¨β¬›β¬›β¬› 207, max 5
β¬›β¬›β¬›πŸŸ¨β¬› 19
β¬›πŸŸ¨β¬›β¬›πŸŸ© 3
πŸŸ¨β¬›β¬›πŸŸ©πŸŸ© 1, finally
🟩🟩🟩🟩🟩
Old had the lucky starter today, proving that so much comes down to this. Only in the long run do we get to see how we are doing as a strategy...
 
Wordle 860 4/6* new
πŸŸ¨β¬›β¬›πŸŸ¨β¬› 67, max 5
β¬›πŸŸ¨β¬›β¬›πŸŸ© 7, max 4
πŸŸ¨πŸŸ©β¬›πŸŸ©πŸŸ© 1...
🟩🟩🟩🟩🟩

Wordle 860 4/6* old
β¬›πŸŸ¨β¬›β¬›β¬› 236, max 5
β¬›πŸŸ©β¬›β¬›πŸŸ¨ 7, max 4
β¬›πŸŸ©πŸŸ¨β¬›πŸŸ¨ 1...
🟩🟩🟩🟩🟩
A tie really today.
 
Wordle 861 3/6* old
β¬›β¬›β¬›πŸŸ¨β¬› 159, max 5
πŸŸ¨β¬›πŸŸ¨πŸŸ¨β¬› 2, max 4
🟩🟩🟩🟩🟩 won 50/50

Wordle 861 3/6* new
β¬›πŸŸ©β¬›β¬›β¬› 62, max 5
β¬›πŸŸ©πŸŸ¨β¬›β¬› 6, max 4
🟩🟩🟩🟩🟩 suggested word was only guarantee of 4, also the solution (luck)
Both methods lucky today, no real difference.
 

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