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Wordle 1,140 3/6* old
β¬›πŸŸ©β¬›β¬›β¬› 107, max 5
β¬›πŸŸ©πŸŸ©β¬›πŸŸ© 5, max 4
🟩🟩🟩🟩🟩 big luck in a sea of green

Wordle 1,140 5/6* new
β¬›β¬›β¬›πŸŸ¨πŸŸ¨ 97, max 6
πŸŸ¨πŸŸ¨β¬›πŸŸ¨β¬› 18, max 6
β¬›πŸŸ©πŸŸ¨πŸŸ¨β¬› 7, max 6
β¬›πŸŸ©πŸŸ©β¬›πŸŸ© 2, max 6
🟩🟩🟩🟩🟩 50/50 - nearest I've been to 6 for a long time

Wordle 1,140 4/6* Jul24
β¬›β¬›πŸŸ¨πŸŸ¨β¬› 138, max 6
πŸŸ¨πŸŸ©β¬›πŸŸ¨β¬› 5, max 5
πŸŸ©πŸŸ©πŸŸ©β¬›πŸŸ© 1..
🟩🟩🟩🟩🟩
The newest starter was better, today.
 
Wordle 1,140 3/6* old
β¬›πŸŸ©β¬›β¬›β¬› 107, max 5
β¬›πŸŸ©πŸŸ©β¬›πŸŸ© 5, max 4
🟩🟩🟩🟩🟩 big luck in a sea of green

Wordle 1,140 5/6* new
β¬›β¬›β¬›πŸŸ¨πŸŸ¨ 97, max 6
πŸŸ¨πŸŸ¨β¬›πŸŸ¨β¬› 18, max 6
β¬›πŸŸ©πŸŸ¨πŸŸ¨β¬› 7, max 6
β¬›πŸŸ©πŸŸ©β¬›πŸŸ© 2, max 6
🟩🟩🟩🟩🟩 50/50 - nearest I've been to 6 for a long time

Wordle 1,140 4/6* Jul24
β¬›β¬›πŸŸ¨πŸŸ¨β¬› 138, max 6
πŸŸ¨πŸŸ©β¬›πŸŸ¨β¬› 5, max 5
πŸŸ©πŸŸ©πŸŸ©β¬›πŸŸ© 1..
🟩🟩🟩🟩🟩
The newest starter was better, today.
To evaluate the efficacy of each algorithm, should the starter be the same for each?
 
To evaluate the efficacy of each algorithm, should the starter be the same for each?
I'm using same algorithm with different starters, to see if how the algorithm works in practice since I do not want to do a big recursive run to check all complete outcomes in a massive run taking lots of compute. This is a simple low impact piece of code that costs mw-seconds of compute and for me the fun is how to achieve code that seems to account for the possibilities without trying them all. Big Blue did chess partly (mostly?) by brute force, I'm trying a almost-zero force to see how well I understand the game play and then embed that in code. And then enjoy playing day by day.
Some claim to have examined all outcomes (based on their fixed assumptions) but they use words like fowth and words that their code knows are not answers which I regard as a foul. They actually use the exact Wordle rules of "hard mode", which allows you to continue to play letters that are not in the solution, again I think that is a small cheat as it gives you more words to choose and slightly better odds...

Each starter was actually the best starter for all possible words at the then current stage of development of my ideas and code. I'm hoping I'm learning and the code (and thus the starter) is getting better, time might tell.
Hmm, so in a way I'm partly using different algorithms, the starters were the result of various algorithms but I play them with my latest code now.
 
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Before I start I'm betting I won't get more than one 3, let's see...

Wordle 1,141 3/6* old
β¬›πŸŸ¨β¬›πŸŸ¨β¬› 44, max 4
πŸŸ©β¬›πŸŸ©πŸŸ©πŸŸ© 1....
🟩🟩🟩🟩🟩 filled my quota already...
(I always enjoyed estimation whist.)

Wordle 1,141 4/6* medium age
β¬›β¬›β¬›πŸŸ¨πŸŸ¨ 97, max 5
πŸŸ¨πŸŸ¨β¬›πŸŸ©β¬› 9, max 5
πŸŸ¨β¬›πŸŸ¨πŸŸ©πŸŸ© 2, max 5
🟩🟩🟩🟩🟩 50/50 (mmm, maybe my estimate will pan out)

Wordle 1,141 4/6* July24
β¬›β¬›πŸŸ¨πŸŸ©β¬› 38, max 5 (I guessed more, maybe 90 possibles)
β¬›πŸŸ¨β¬›πŸŸ©πŸŸ© 5, max 4
πŸŸ¨β¬›β¬›πŸŸ©πŸŸ© 1...
🟩🟩🟩🟩🟩
Won my little self-bet though.

Average is reported as 3.4 - well beaten again gents!
 
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OK, kets see if the code can avoid the trap... a good test maybe today
Wordle 1,142 4/6* old
β¬›πŸŸ¨β¬›β¬›β¬› 236, max 5
β¬›πŸŸ¨πŸŸ¨πŸŸ¨β¬› 7, max 4
β¬›β¬›πŸŸ¨πŸŸ¨πŸŸ© 1...
🟩🟩🟩🟩🟩

Wordle 1,142 4/6* medium
β¬›πŸŸ©β¬›πŸŸ©πŸŸ¨ only 3, but max 4
πŸŸ©πŸŸ©β¬›πŸŸ©πŸŸ© 2, max 4
πŸŸ©πŸŸ©β¬›πŸŸ©πŸŸ© 1..
🟩🟩🟩🟩🟩 last possible (of a small group which it saw as a lesser evil, I guess)

Wordle 1,142 3/6* Jul24
πŸŸ¨β¬›πŸŸ¨πŸŸ¨β¬› 8, max 5
β¬›πŸŸ©πŸŸ©πŸŸ©πŸŸ¨ 1...
🟩🟩🟩🟩🟩
Average reported as 4.5 "very taxing", today.
 
Wordle 1,143 4/6* old
β¬›β¬›πŸŸ¨πŸŸ¨β¬› 40, max 5
πŸŸ¨β¬›β¬›πŸŸ©β¬› 4, max 4
β¬›β¬›πŸŸ¨πŸŸ©πŸŸ¨ 1...
🟩🟩🟩🟩🟩

Wordle 1,143 4/6* medium
β¬›β¬›β¬›πŸŸ¨β¬› 247, max 6
β¬›β¬›πŸŸ¨β¬›πŸŸ© 12, max 5
πŸŸ¨πŸŸ¨β¬›β¬›πŸŸ© 1...
🟩🟩🟩🟩🟩

Wordle 1,143 4/6* Jul24
β¬›β¬›πŸŸ¨β¬›β¬› 427, max 6
β¬›β¬›β¬›πŸŸ¨πŸŸ¨ 31, max 5
β¬›πŸŸ¨πŸŸ¨β¬›β¬› 3, max 5
🟩🟩🟩🟩🟩 luck (but a green flash)
Average reported as 4.0, "very taxing".
 

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